3.20.39 \(\int \sqrt {d+e x} (a+b x+c x^2) \, dx\)

Optimal. Leaf size=75 \[ \frac {2 (d+e x)^{3/2} \left (a e^2-b d e+c d^2\right )}{3 e^3}-\frac {2 (d+e x)^{5/2} (2 c d-b e)}{5 e^3}+\frac {2 c (d+e x)^{7/2}}{7 e^3} \]

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Rubi [A]  time = 0.03, antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {698} \begin {gather*} \frac {2 (d+e x)^{3/2} \left (a e^2-b d e+c d^2\right )}{3 e^3}-\frac {2 (d+e x)^{5/2} (2 c d-b e)}{5 e^3}+\frac {2 c (d+e x)^{7/2}}{7 e^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[d + e*x]*(a + b*x + c*x^2),x]

[Out]

(2*(c*d^2 - b*d*e + a*e^2)*(d + e*x)^(3/2))/(3*e^3) - (2*(2*c*d - b*e)*(d + e*x)^(5/2))/(5*e^3) + (2*c*(d + e*
x)^(7/2))/(7*e^3)

Rule 698

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d +
e*x)^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*
e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && IntegerQ[p] && (GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps

\begin {align*} \int \sqrt {d+e x} \left (a+b x+c x^2\right ) \, dx &=\int \left (\frac {\left (c d^2-b d e+a e^2\right ) \sqrt {d+e x}}{e^2}+\frac {(-2 c d+b e) (d+e x)^{3/2}}{e^2}+\frac {c (d+e x)^{5/2}}{e^2}\right ) \, dx\\ &=\frac {2 \left (c d^2-b d e+a e^2\right ) (d+e x)^{3/2}}{3 e^3}-\frac {2 (2 c d-b e) (d+e x)^{5/2}}{5 e^3}+\frac {2 c (d+e x)^{7/2}}{7 e^3}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 55, normalized size = 0.73 \begin {gather*} \frac {2 (d+e x)^{3/2} \left (7 e (5 a e-2 b d+3 b e x)+c \left (8 d^2-12 d e x+15 e^2 x^2\right )\right )}{105 e^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[d + e*x]*(a + b*x + c*x^2),x]

[Out]

(2*(d + e*x)^(3/2)*(7*e*(-2*b*d + 5*a*e + 3*b*e*x) + c*(8*d^2 - 12*d*e*x + 15*e^2*x^2)))/(105*e^3)

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IntegrateAlgebraic [A]  time = 0.04, size = 62, normalized size = 0.83 \begin {gather*} \frac {2 (d+e x)^{3/2} \left (35 a e^2+21 b e (d+e x)-35 b d e+35 c d^2-42 c d (d+e x)+15 c (d+e x)^2\right )}{105 e^3} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[Sqrt[d + e*x]*(a + b*x + c*x^2),x]

[Out]

(2*(d + e*x)^(3/2)*(35*c*d^2 - 35*b*d*e + 35*a*e^2 - 42*c*d*(d + e*x) + 21*b*e*(d + e*x) + 15*c*(d + e*x)^2))/
(105*e^3)

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fricas [A]  time = 0.41, size = 84, normalized size = 1.12 \begin {gather*} \frac {2 \, {\left (15 \, c e^{3} x^{3} + 8 \, c d^{3} - 14 \, b d^{2} e + 35 \, a d e^{2} + 3 \, {\left (c d e^{2} + 7 \, b e^{3}\right )} x^{2} - {\left (4 \, c d^{2} e - 7 \, b d e^{2} - 35 \, a e^{3}\right )} x\right )} \sqrt {e x + d}}{105 \, e^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)*(e*x+d)^(1/2),x, algorithm="fricas")

[Out]

2/105*(15*c*e^3*x^3 + 8*c*d^3 - 14*b*d^2*e + 35*a*d*e^2 + 3*(c*d*e^2 + 7*b*e^3)*x^2 - (4*c*d^2*e - 7*b*d*e^2 -
35*a*e^3)*x)*sqrt(e*x + d)/e^3

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giac [B]  time = 0.16, size = 200, normalized size = 2.67 \begin {gather*} \frac {2}{105} \, {\left (35 \, {\left ({\left (x e + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {x e + d} d\right )} b d e^{\left (-1\right )} + 7 \, {\left (3 \, {\left (x e + d\right )}^{\frac {5}{2}} - 10 \, {\left (x e + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {x e + d} d^{2}\right )} c d e^{\left (-2\right )} + 7 \, {\left (3 \, {\left (x e + d\right )}^{\frac {5}{2}} - 10 \, {\left (x e + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {x e + d} d^{2}\right )} b e^{\left (-1\right )} + 3 \, {\left (5 \, {\left (x e + d\right )}^{\frac {7}{2}} - 21 \, {\left (x e + d\right )}^{\frac {5}{2}} d + 35 \, {\left (x e + d\right )}^{\frac {3}{2}} d^{2} - 35 \, \sqrt {x e + d} d^{3}\right )} c e^{\left (-2\right )} + 105 \, \sqrt {x e + d} a d + 35 \, {\left ({\left (x e + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {x e + d} d\right )} a\right )} e^{\left (-1\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)*(e*x+d)^(1/2),x, algorithm="giac")

[Out]

2/105*(35*((x*e + d)^(3/2) - 3*sqrt(x*e + d)*d)*b*d*e^(-1) + 7*(3*(x*e + d)^(5/2) - 10*(x*e + d)^(3/2)*d + 15*
sqrt(x*e + d)*d^2)*c*d*e^(-2) + 7*(3*(x*e + d)^(5/2) - 10*(x*e + d)^(3/2)*d + 15*sqrt(x*e + d)*d^2)*b*e^(-1) +
3*(5*(x*e + d)^(7/2) - 21*(x*e + d)^(5/2)*d + 35*(x*e + d)^(3/2)*d^2 - 35*sqrt(x*e + d)*d^3)*c*e^(-2) + 105*s
qrt(x*e + d)*a*d + 35*((x*e + d)^(3/2) - 3*sqrt(x*e + d)*d)*a)*e^(-1)

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maple [A]  time = 0.05, size = 53, normalized size = 0.71 \begin {gather*} \frac {2 \left (e x +d \right )^{\frac {3}{2}} \left (15 c \,e^{2} x^{2}+21 b \,e^{2} x -12 c d e x +35 a \,e^{2}-14 b d e +8 c \,d^{2}\right )}{105 e^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+b*x+a)*(e*x+d)^(1/2),x)

[Out]

2/105*(e*x+d)^(3/2)*(15*c*e^2*x^2+21*b*e^2*x-12*c*d*e*x+35*a*e^2-14*b*d*e+8*c*d^2)/e^3

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maxima [A]  time = 0.86, size = 59, normalized size = 0.79 \begin {gather*} \frac {2 \, {\left (15 \, {\left (e x + d\right )}^{\frac {7}{2}} c - 21 \, {\left (2 \, c d - b e\right )} {\left (e x + d\right )}^{\frac {5}{2}} + 35 \, {\left (c d^{2} - b d e + a e^{2}\right )} {\left (e x + d\right )}^{\frac {3}{2}}\right )}}{105 \, e^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)*(e*x+d)^(1/2),x, algorithm="maxima")

[Out]

2/105*(15*(e*x + d)^(7/2)*c - 21*(2*c*d - b*e)*(e*x + d)^(5/2) + 35*(c*d^2 - b*d*e + a*e^2)*(e*x + d)^(3/2))/e
^3

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mupad [B]  time = 0.06, size = 58, normalized size = 0.77 \begin {gather*} \frac {2\,{\left (d+e\,x\right )}^{3/2}\,\left (15\,c\,{\left (d+e\,x\right )}^2+35\,a\,e^2+35\,c\,d^2+21\,b\,e\,\left (d+e\,x\right )-42\,c\,d\,\left (d+e\,x\right )-35\,b\,d\,e\right )}{105\,e^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x)^(1/2)*(a + b*x + c*x^2),x)

[Out]

(2*(d + e*x)^(3/2)*(15*c*(d + e*x)^2 + 35*a*e^2 + 35*c*d^2 + 21*b*e*(d + e*x) - 42*c*d*(d + e*x) - 35*b*d*e))/
(105*e^3)

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sympy [A]  time = 3.03, size = 71, normalized size = 0.95 \begin {gather*} \frac {2 \left (\frac {c \left (d + e x\right )^{\frac {7}{2}}}{7 e^{2}} + \frac {\left (d + e x\right )^{\frac {5}{2}} \left (b e - 2 c d\right )}{5 e^{2}} + \frac {\left (d + e x\right )^{\frac {3}{2}} \left (a e^{2} - b d e + c d^{2}\right )}{3 e^{2}}\right )}{e} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+b*x+a)*(e*x+d)**(1/2),x)

[Out]

2*(c*(d + e*x)**(7/2)/(7*e**2) + (d + e*x)**(5/2)*(b*e - 2*c*d)/(5*e**2) + (d + e*x)**(3/2)*(a*e**2 - b*d*e +
c*d**2)/(3*e**2))/e

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